Print a Kendo UI grid with pagination

So I wanted to print a page that has a Kendo ui grid with pagination activated, but I didn’t want to remove the pagination on the page.

I found those two posts that helped me

And I ended with this

(function () {

var pageSize = 0;
 var beforePrint = function () {

 // remove paging on grid
 if ($(".k-grid").length > 0) {
 var dataSource = $(".k-grid").data("kendoGrid").dataSource;
 pageSize = dataSource.options.pageSize; // save the current page size
if(pageSize !== undefined){
 dataSource.pageSize(; // set the size to the number of items


var afterPrint = function () {

// set paging back
 if ($(".k-grid").length > 0 && pageSize > 0) {
 var dataSource = $(".k-grid").data("kendoGrid").dataSource;

// chrome
 if (window.matchMedia) {
 var mediaQueryList = window.matchMedia('print');
 mediaQueryList.addListener(function (mql) {
 if (mql.matches) {
 } else {

// FF & IE
 window.onbeforeprint = beforePrint;
 window.onafterprint = afterPrint;


Hope it helps someone


A few resources about ASP.NET vNext

Intro by Scott Hanselman :

Intro by David Fowler :

  • A better platform for building web applications with .NET
  • Things we wanted to fix
  • System.Web

Overview by David Fowler :

Intro by Jeff Fritz:

  • Introducing OWIN
  • MVC – Meet WebAPI, WebAPI meet MVC
  • Bye Bye System.Web
  • Blistering Performance
  • Where is web.config?
  • Welcome Project.JSON!

Videos :

Scott Hanselman and Scott Hunter : INTRODUCING: The Future of .NET on the Server

David Fowler and Scott Hanselman : DEEP DIVE: The Future of .NET on the Server


Source code :

Asp.Net vNext is open source and can be found on github :

The current version of ASP.NET is still on codeplex :

Know your .NET Framework Episode 2 : getting a range of integers

If you need a list of integers filled with all numbers in a specific range, you will often do this :

List<int> range = new List<int>();
for (int i = rangeStart; i < RangeEnd; i++)

or you will write a method

public IEnumerable<int> GetRange(int start, int end)
  for (int i = start; i < end; i++)
    yield return i;

and call it:

List<int> range = GetRange(0, 10).ToList();

Good news : this method already exists in the framework !

You can find it in the System.Linq namespace : it’s the Enumerable.Range static method, and it’s available since framework 3.5.

This method returns an IEnumerable<int>, you can use it like this, or convert it to an array or a list.
to use it :
List<int> range = new List<int>(Enumerable.Range(0, 10));
List<int> range = Enumerable.Range(0, 10)).ToList();


Note that the first parameter is the start, but the second is not the end ! it’s a count !, so if you want to use it by specifying a start and an end you will have to do this :

int start = 5;
int end = 50;
List<int> range = Enumerable.Range(start, (end-start)+1)).ToList();

It’s handy to reduce the code size when you want to fill a dropdown or other things that requires a range of integers.

Know your .NET Framework Episode 1 : joining strings

Too often we see developers re-inventing the wheel, so I’d like to try to make a round-up of the common methods people don’t use enough

I’m not saying I’ never made the same mistakes, but I’m going to try to group them to avoid you (and me) to do them again

First example : how to properly join a list of strings (jump to the conclusion if you want the direct answer)

imagine you have a list of strings :

IEnumerable<string> mylist = new[] { "dog", "cat", "turtle", "bird", "fish" };

and as a result you would like

dog, cat, turtle, bird, fish

so joining all items by a comma followed by a blank space

what devs usually do is :

string result = "";
foreach(string item in mylist) // joining all items
  result += item + ", ";

which will result in

dog, cat, turtle, bird, fish,

so they will remove the trailing “, ”

string result = "";
foreach(string item in mylist) // joining all items
  result += item + ", ";

result =result.TrimEnd(new char[] { ',', ' ' });

// or result =  result.Remove(result.LastIndexOf(", "), 2);
// or another method

this will give the wanted “dog, cat, turtle, bird, fish”

Another way to go is

 List<string> mylist = new List<string>(new []{ "dog", "cat", "turtle", "bird", "fish" });
 string result = "";
 for (int i = 0; i < mylist.Count; i++)
   if (i != 0)
      result += ", ";
   result += mylist[i];

This will work as well

But there is a method that was there for ever (I mean since the first version of the framework)

This is a static method of the String class: the Join method.

It has several signatures, but basically it takes the separator you want as the first parameter, and a collection of string or object as second parameter.

If you want to see how it’s implemented : check the method in the framework source reference


You can really shorten you code by using this method

string result = String.Join(", ",mylist);


Of course you don’t have to limit yourself to a comma as a separator, here is an example to create an html unordered list:

List<string> mylist = new List<string>(new []{ "dog", "cat", "turtle", "bird", "fish" });

// step 1 :create the inner "li"
string listItems = string.Join("</li><li>", mylist);

// step 2 : complete the first and last "li" and surround by an "ul"
string result = string.Format("<ul><li>{0}</li></ul>",listItems);

output :


or :

  • dog
  • cat
  • turtle
  • bird
  • fish