Know your .NET Framework Episode 2 : getting a range of integers

If you need a list of integers filled with all numbers in a specific range, you will often do this :

List<int> range = new List<int>();
for (int i = rangeStart; i < RangeEnd; i++)
{
   range.Add(i);
}

or you will write a method

public IEnumerable<int> GetRange(int start, int end)
{
  for (int i = start; i < end; i++)
  {
    yield return i;
  }
}

and call it:

List<int> range = GetRange(0, 10).ToList();

Good news : this method already exists in the framework !

You can find it in the System.Linq namespace : it’s the Enumerable.Range static method, and it’s available since framework 3.5.

This method returns an IEnumerable<int>, you can use it like this, or convert it to an array or a list.
to use it :
List<int> range = new List<int>(Enumerable.Range(0, 10));
or
List<int> range = Enumerable.Range(0, 10)).ToList();

Remark

Note that the first parameter is the start, but the second is not the end ! it’s a count !, so if you want to use it by specifying a start and an end you will have to do this :

int start = 5;
int end = 50;
List<int> range = Enumerable.Range(start, (end-start)+1)).ToList();

It’s handy to reduce the code size when you want to fill a dropdown or other things that requires a range of integers.

Know your .NET Framework Episode 1 : joining strings

Too often we see developers re-inventing the wheel, so I’d like to try to make a round-up of the common methods people don’t use enough

I’m not saying I’ never made the same mistakes, but I’m going to try to group them to avoid you (and me) to do them again

First example : how to properly join a list of strings (jump to the conclusion if you want the direct answer)

imagine you have a list of strings :


IEnumerable<string> mylist = new[] { "dog", "cat", "turtle", "bird", "fish" };

and as a result you would like

dog, cat, turtle, bird, fish

so joining all items by a comma followed by a blank space

what devs usually do is :


string result = "";
foreach(string item in mylist) // joining all items
{
  result += item + ", ";
}

which will result in

dog, cat, turtle, bird, fish,

so they will remove the trailing “, ”


string result = "";
foreach(string item in mylist) // joining all items
{
  result += item + ", ";
}

result =result.TrimEnd(new char[] { ',', ' ' });

// or result =  result.Remove(result.LastIndexOf(", "), 2);
// or another method

this will give the wanted “dog, cat, turtle, bird, fish”

Another way to go is

 List<string> mylist = new List<string>(new []{ "dog", "cat", "turtle", "bird", "fish" });
 string result = "";
 for (int i = 0; i < mylist.Count; i++)
 {
   if (i != 0)
   {
      result += ", ";
   }
   result += mylist[i];
}

This will work as well

But there is a method that was there for ever (I mean since the first version of the framework)

This is a static method of the String class: the Join method.

It has several signatures, but basically it takes the separator you want as the first parameter, and a collection of string or object as second parameter.

If you want to see how it’s implemented : check the method in the framework source reference

Conclusion

You can really shorten you code by using this method

string result = String.Join(", ",mylist);

Bonus

Of course you don’t have to limit yourself to a comma as a separator, here is an example to create an html unordered list:

List<string> mylist = new List<string>(new []{ "dog", "cat", "turtle", "bird", "fish" });

// step 1 :create the inner "li"
string listItems = string.Join("</li><li>", mylist);

// step 2 : complete the first and last "li" and surround by an "ul"
string result = string.Format("<ul><li>{0}</li></ul>",listItems);

output :

<ul><li>dog</li><li>cat</li><li>turtle</li><li>bird</li><li>fish</li></ul>

or :

  • dog
  • cat
  • turtle
  • bird
  • fish

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